Correction dm svp

Bonjour , pouvez vous me corriger svp . Merci d'avance .

Exercice 2

(3*x-2)^2+(x+3)^2=9*x^2-12*x+4+x^2+6*x+9=10*x^2-6*x+13
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(3*u+4)^2+(6*u-4)(4-5*u)=9*u^2+24*u+16+6*u*(4-5*u)-4*(4-5*u)
=9*u^2+24*u+16+24*u-30*u^2-16+20*u=-21*u^2+68*u
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(x/3-3/2)^2=x^2/9-x+9/4
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(5*a-4)*(a^2+2)=5*a*(a^2+2)-4*(a^2+2)=5*a^3+10*a-4*a^2-8=5*a^3-4*a^2+10*a-8
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(2*x/3-2)^2-(x-4)*(x-4)=4*x^2/9-8*x/3+4-(x^2-8*x+16)=
=4*x^2/9-8*x/3+4-x^2+8*x-16=-5*x^2/9+16*x/3-12



exercice1

A=4.3*10^(-3)*60/(15*10^(-4))=4.3*4*10^(-3+4)=172=1.72*10^(2)

B=200*100^2*4/((10^(4))^2*(-5)*10^(4))=200*10^4*4/((10^(8)*(-5)*10^(4))=-40*4/((10^(8))=-160*10^(-8)=-1.6*10^(-6)=-0.0000016

Bonjour,

Selon moi tout est correct.
Attention (pour les esprits pointilleux, et les profs de math le sont parfois...) dans l'exercice 1, il est bien précisé: donner le résultat en écriture décimale PUIS en écriture scientifique.
Ainsi, pour le B, il convient de dire:
B = - 0.0000016 (écriture décimale) et B = - 1.6 * 10^(-6)

Pour l'exercice 2, il manque:

(4x + 1)(6 - x) = ... = - 4x² + 23x + 6

Pour le reste, sauf erreur de part aussi, tout est correct.

Bon dimanche.

Merci beaucoup

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Modifié 1 fois. Dernière modification le 09/05/12 09:19 par karenmillen.